Given Log10x = 2a and Log10y = B/2. Write 10a In Terms of X.

Given log₁₀x = 2a and log₁₀y = `b/2`. Write 10^a in terms of x.

Sum

log₁₀x = 2a
⇒ x = 10^2a ...[ Removing logarithm from both sides ]
⇒ x^1/2 = 10^a
⇒ 10^a = x^1/2

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Chapter 8: Logarithms - Exercise 8 (D) [Page 111]

Chapter 8 Logarithms
Exercise 8 (D) | Q 13.1 | Page 111

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