Advertisements
Advertisements
Question
Given log10x = 2a and log10y = `b/2`. Write 10a in terms of x.
Advertisements
Solution
log10x = 2a
⇒ x = 102a ...[ Removing logarithm from both sides ]
⇒ x1/2 = 10a
⇒ 10a = x1/2
APPEARS IN
RELATED QUESTIONS
If x = log 0.6; y = log 1.25 and z = log 3 - 2 log 2, find the values of :
(i) x+y- z
(ii) 5x + y - z
If a2 = log x, b3 = log y and 3a2 - 2b3 = 6 log z, express y in terms of x and z .
Evaluate: logb a × logc b × loga c.
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Solve the following:
log(x2 + 36) - 2log x = 1
Solve the following:
log (x + 1) + log (x - 1) = log 48
State, true of false:
If `("log"49)/("log"7)` = log y, then y = 100.
Find x and y, if `("log"x)/("log"5) = ("log"36)/("log"6) = ("log"64)/("log"y)`
Express the following in a form free from logarithm:
3 log x - 2 log y = 2
Prove that log 10 125 = 3 (1 - log 10 2)
