Question

From the simplification \[m = \frac{14 \pm 12}{2}\], which are the two roots of \[m^{2} - 14m + 13 = 0\]?

Options

• \[m = 13\] and \[m = 1\]

• \[m = 14\] and \[m = 12\]

• \[m = 13\] and \[m = -1\]

• \[m = 26\] and \[m = 2\]

Answer 1

\[m = \frac{14 + 12}{2} = \frac{26}{2} = 13\] and \[m = \frac{14 - 12}{2} = \frac{2}{2} = 1\]. Hence the roots are \[m = 13\] and \[m = 1\], which satisfy the original equation \[m^{2} - 14m + 13 = 0\].