Question

Four resistances of \(2.0 \Omega\) each are joined end to end to form a square ABCD. Calculate the equivalent resistance of the combination between any two adjacent corners.

Answer 1

Between adjacent corners, one path has a single \(2\ \Omega\) resistor; the other path has the remaining three in series:

\[R_{\text{other}}=2+2+2\]

= 6 Ω

These two paths are in parallel:

\[R_{\mathrm{eq}}=\frac{2\times6}{2+6}\]

= 1.5 Ω