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Four elements A, B, C and D have the following electron arrangements in their atoms: A 2, 8, 6 B 2, 8, 8 C 2, 8, 8, 1 D 2, 7 (a) What type of bond is formed when element C combines with element D?

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Question

Four elements A, B, C and D have the following electron arrangements in their atoms:

A 2, 8, 6
B 2, 8, 8
C 2, 8, 8, 1
D 2, 7
  1. What type of bond is formed when element C combines with element D?
  2. Which element is an inert gas?
  3. What will be the formula of the compound between A and C?
Very Long Answer
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Solution

  1. An ionic bond is formed between element C and element D. One valence electron is completely transferred from an atom of element C to an atom of element D.
  2. Element B is an inert gas. It features 8 electrons in its outermost shell, giving it a completely filled, stable valence configuration.
  3. The chemical formula of the compound is C2A. Element A (2, 8, 6) needs 2 electrons to complete its octet, while each atom of element C (2, 8, 8, 1) can lose 1 electron. Therefore, two atoms of C transfer their electrons to one atom of A. Writing the metal first yields C2A.
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Chapter 3: Metals and Non-metals - Exercise 2 [Page 209]

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Lakhmir Singh Chemistry [English] Class 10
Chapter 3 Metals and Non-metals
Exercise 2 | Q 74. | Page 209
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