Question

For \[y=e^{-3x}\], what is \[\frac{d^{2}y}{dx^{2}}\]?

Options

• \[\frac{d^{2}y}{dx^{2}}=6e^{-3x}\]

• \[\frac{d^{2}y}{dx^{2}}=-3e^{-3x}\]

• \[\frac{d^{2}y}{dx^{2}}=9e^{-3x}\]

• \[\frac{d^{2}y}{dx^{2}}=-9e^{-3x}\]

Answer 1

Differentiating \[-3e^{-3x}\] once more gives \[(-3)(-3)e^{-3x}\]. Thus, \[\frac{d^{2}y}{dx^{2}}=9e^{-3x}\].