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Question
For \[x>0\], differentiate \[\sin(\log x)\] with respect to \[x\].
Options
\[-\frac{\cos(\log x)}{x}\]
\[\frac{\cos(\log x)}{x}\]
\[\cos(\log x)\]
\[\frac{\sin(\log x)}{x}\]
MCQ
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Solution
The derivative of \[\sin(\log x)\] is \[\cos(\log x)\] times the derivative of \[\log x\]. Since \[\frac{d}{dx}(\log x)=\frac{1}{x}\], the derivative is \[\frac{\cos(\log x)}{x}\].
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