Question

For what value of $$k$$ will $$2k + 1, 3k + 3$$ and $$5k - 1$$ be three consecutive terms of an A.P.?

Options

• $$1$$

• $$2$$

• $$4$$

• $$6$$

Answer 1

6

Explanation: 

The condition is $$2(3k + 3) = (2k + 1) + (5k - 1)$$, giving $$k = 6$$.