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Question
For the reaction, \[\ce{A +2B → AB2}\], the order w.r.t. reactant A is 2 and w.r.t. reactant B. What will be change in rate of reaction if the concentration of A is doubled and B is halved?
Options
Increases four times
Decreases four times
Increases two times
No change
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Solution
Increases four times
Explanation:
Rate = [A]2
If [A] is doubled then Rate = [2A]2 = 4[A]2 = 4 Rate
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