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For the harmonic travelling wave y = 2 cos 2π (10t – 0.0080x + 3.5) where x and y are in cm and t is second. - Physics

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Question

For the harmonic travelling wave y = 2 cos 2π (10t – 0.0080x + 3.5) where x and y are in cm and t is second. What is the phase difference between the oscillatory motion at two points separated by a distance of `(3λ)/4` (at a given instant of time)

Numerical
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Solution

Given, wave functions are y = 2 cos 2π (10t – 0.0080x + 3.5) 

= 2 cos(20πt – 0.016πx + 7π)

Now, the standard equation of a travelling wave can be written as y = a cos(ωt – kx + `phi`)

On comparing with the above equation, we get

a = 2 cm

ω = 20π rad/s

k = 0.016π

Path difference = 4 cm

Δ`phi = (2π)/λ xx (3λ)/4 = (3π)/2` rad

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Chapter 15: Waves - Exercises [Page 112]

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NCERT Exemplar Physics [English] Class 11
Chapter 15 Waves
Exercises | Q 15.36 (d) | Page 112

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