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Question
For the following repeater machines, how many times the base machine is applied and how much the total stretch is?
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Solution
In machine (a), (× 1002) = 10000 stretch.
Since, it is two times the base machine.
In machine (b), (× 75) = 16807 stretch.
Since, it is fair times the base machine.
In machine (c), (× 57) = 78125 stretch.
Since, it is 7 times the base machine.
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