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प्रश्न
For the following repeater machines, how many times the base machine is applied and how much the total stretch is?

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उत्तर
In machine (a), (× 1002) = 10000 stretch.
Since, it is two times the base machine.
In machine (b), (× 75) = 16807 stretch.
Since, it is fair times the base machine.
In machine (c), (× 57) = 78125 stretch.
Since, it is 7 times the base machine.
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संबंधित प्रश्न
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| Element | Mass of atom (kg) |
| Titanium | 7.95 × 10–26 |
| Lead | 3.44 × 10–25 |
| Silver | 1.79 × 10–25 |
| Lithium | 1.15 × 10–26 |
| Hydrogen | 1.674 × 10–27 |
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