English

For the curve x+y = 1, dydxdydx at (14,14) is ______.

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Question

For the curve `sqrt(x) + sqrt(y)` = 1, `"dy"/"dx"` at `(1/4, 1/4)` is ______.

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Solution

For the curve `sqrt(x) + sqrt(y)` = 1, `"dy"/"dx"` at `(1/4, 1/4)` is – 1.

Explanation:

Given that: `sqrt(x) + sqrt(y)` = 1

Differentiating both sides w.r.t. x

`1/(2sqrt(x)) + 1/(2sqrt(y)) * "dy"/"dx"` = 0

⇒ `1/sqrt(x) + 1/sqrt(y)  "dy"/"dx"` = 0

⇒ `1/sqrt(y) "dy"/"dx" = (-1)/sqrt(x)`

⇒ `"dy"/"dx" = (-sqrt(y))/sqrt(x)`

∴ `"dy"/"dx"` at `(1/4, 1/4) = - sqrt(1/4)/sqrt(1/4)`

= – 1.

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Chapter 5: Continuity And Differentiability - Exercise [Page 116]

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NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 5 Continuity And Differentiability
Exercise | Q 101 | Page 116

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