Advertisements
Advertisements
Question
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.

Advertisements
Solution
Using law of exponents,
am × an = (a)m + n ...[∵ a is non-zero integer]
Hook-up machine can do the work = 73 × 72 = 75
So, (x 75) single machine can do the same work.
Diagram of single × 75 machine.

APPEARS IN
RELATED QUESTIONS
For a non-zero integer x, (x4)–3 is equal to ______.
(–7)–4 × (–7)2 = (–7)–2
The value of 5–2 is equal to 25.
Express as a power of a rational number with negative exponent.
`(((-3)/2)^-2)^-3`
`(125 xx x^-3)/(5^-3 xx 25 xx x^-6)`
An insect is on the 0 point of a number line, hopping towards 1. She covers half the distance from her current location to 1 with each hop. So, she will be at `1/2` after one hop, `3/4` after two hops, and so on.

- Make a table showing the insect’s location for the first 10 hops.
- Where will the insect be after n hops?
- Will the insect ever get to 1? Explain.
If possible, find a hook-up of prime base number machine that will do the same work as the given stretching machine. Do not use (× 1) machines.

Find a repeater machine that will do the same work as a `(xx 1/8)` machine.
By what number should (–15)–1 be divided so that the quotient may be equal to (–5)–1?
Simplify:
`((3^-2)^2 xx (5^2)^-3 xx (t^-3)^2)/((3^-2)^5 xx (5^3)^-2 xx (t^-4)^3`
