Advertisements
Advertisements
Question
Find x, if
\[\left( \frac{3}{2} \right)^{- 3} \times \left( \frac{3}{2} \right)^5 = \left( \frac{3}{2} \right)^{2x + 1}\]
Sum
Advertisements
Solution
We have:
\[\left( \frac{3}{2} \right)^{- 3} \times \left( \frac{3}{2} \right)^5 = \left( \frac{3}{2} \right)^{2x + 1}\]
`(3/2)^2=(3/2)^(2x+1)`
2 = 2x + 1
1 = 2x
`1/2=x`
x = `1/2`
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Express the following as a rational number of the form \[\frac{p}{q},\] where p and q are integers and q ≠ 0. (−4)−2
Express the following rational numbers with a positive exponent:
\[\left\{ \left( \frac{4}{3} \right)^{- 3} \right\}^{- 4}\]
Simplify:
\[\left( 3^2 - 2^2 \right) \times \left( \frac{2}{3} \right)^{- 3}\]
Cube of \[\frac{- 1}{2}\] is
\[\left( \frac{1}{5} \right)^0\] is equal to
For any two rational numbers a and b, a5 × b5 is equal to
Expand the following numbers using exponents.
1025.63
Expand the following numbers using exponents.
1256.249
The multiplicative inverse of 10–100 is ______.
The expression for 4–3 as a power with the base 2 is 26.
