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Question
Find x, if
\[\left( \frac{3}{2} \right)^{- 3} \times \left( \frac{3}{2} \right)^5 = \left( \frac{3}{2} \right)^{2x + 1}\]
Sum
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Solution
We have:
\[\left( \frac{3}{2} \right)^{- 3} \times \left( \frac{3}{2} \right)^5 = \left( \frac{3}{2} \right)^{2x + 1}\]
`(3/2)^2=(3/2)^(2x+1)`
2 = 2x + 1
1 = 2x
`1/2=x`
x = `1/2`
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