Advertisements
Advertisements
Question
Find without division, the remainder in the following:
2x3 - 3x2 + 6x - 4 is divisible by (2x-3)
Advertisements
Solution
2x3 - 3x2 + 6x - 4 is divisible by (2x-3)
Putting 2x - 3 = 0, we get : x = `3/2`
Substituting this value of x in the equation, we get
`2 xx 3/2 xx 3/2 xx 3/2 - 3 xx 3/2 xx 3/2 + 6 xx 3/2 - 4`
`= 27/4 - 27/4 + 9 - 4`
= 5
APPEARS IN
RELATED QUESTIONS
Use the Remainder Theorem to factorise the following expression:]
`2x^3 + x^2 - 13x + 6`
Find the remainder when x4 + 1 is divided by x + 1.
Using the Remainder Theorem, factorise the following completely:
4x3 + 7x2 – 36x – 63
Polynomials bx2 + x + 5 and bx3 − 2x + 5 are divided by polynomial x - 3 and the remainders are m and n respectively. If m − n = 0 then find the value of b.
Find the values of p and q in the polynomial f(x)= x3 - px2 + 14x -q, if it is exactly divisible by (x-1) and (x-2).
Find the remainder when the polynomial f(x) = 2x4 - 6x3 + 2x2 - x + 2 is divided by x + 2.
Use the Remainder Theorem to factorise the following expression:
2x3 + x2 – 13x + 6
If on dividing 4x2 – 3kx + 5 by x + 2, the remainder is – 3 then the value of k is
When 2x3 – 9x2 + 10x – p is divided by (x + 1), the remainder is – 24.Find the value of p.
By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial: x4 + 1; x – 1
