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प्रश्न
Find without division, the remainder in the following:
2x3 - 3x2 + 6x - 4 is divisible by (2x-3)
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उत्तर
2x3 - 3x2 + 6x - 4 is divisible by (2x-3)
Putting 2x - 3 = 0, we get : x = `3/2`
Substituting this value of x in the equation, we get
`2 xx 3/2 xx 3/2 xx 3/2 - 3 xx 3/2 xx 3/2 + 6 xx 3/2 - 4`
`= 27/4 - 27/4 + 9 - 4`
= 5
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