Advertisements
Advertisements
प्रश्न
Find the value of ‘m’, if mx3 + 2x2 – 3 and x2 – mx + 4 leave the same remainder when each is divided by x – 2.
Advertisements
उत्तर
Let f(x) = mx3 + 2x2 – 3
g(x) = x2 – mx + 4
It is given that f(x) and g(x) leave the same remainder when divided by (x – 2).
Therefore, we have:
f(2) = g(2)
m(2)3 + 2(2)2 – 3 = (2)2 – m(2) + 4
8m + 8 – 3 = 4 – 2m + 4
10m = 3
m = `3/10 `
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x+1.
Find the remainder when x3 + 3x2 + 3x + 1 is divided by `x - 1/2`
Use the Remainder Theorem to factorise the following expression:]
`2x^3 + x^2 - 13x + 6`
Use remainder theorem and find the remainder when the polynomial g(x) = x3 + x2 – 2x + 1 is divided by x – 3.
When x3 + 3x2 – kx + 4 is divided by (x – 2), the remainder is k. Find the value of k.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x - 4
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 2x2 – 4x – 1; g(x) = x + 1
If x51 + 51 is divided by x + 1, then the remainder is
Check whether p(x) is a multiple of g(x) or not:
p(x) = 2x3 – 11x2 – 4x + 5, g(x) = 2x + 1
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
