Advertisements
Advertisements
प्रश्न
Find without division, the remainder in the following:
2x3 - 3x2 + 6x - 4 is divisible by (2x-3)
Advertisements
उत्तर
2x3 - 3x2 + 6x - 4 is divisible by (2x-3)
Putting 2x - 3 = 0, we get : x = `3/2`
Substituting this value of x in the equation, we get
`2 xx 3/2 xx 3/2 xx 3/2 - 3 xx 3/2 xx 3/2 + 6 xx 3/2 - 4`
`= 27/4 - 27/4 + 9 - 4`
= 5
APPEARS IN
संबंधित प्रश्न
Check whether 7 + 3x is a factor of 3x3 + 7x.
Find 'a' if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leaves the same remainder when divided by x + 3.
If x3 + ax2 + bx + 6 has x – 2 as a factor and leaves a remainder 3 when divided by x – 3, find the values of a and b.
If (x – 2) is a factor of the expression 2x3 + ax2 + bx – 14 and when the expression is divided by (x – 3), it leaves a remainder 52, find the values of a and b.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x - 4
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3)x – 6 leave the same remainder. Find the value of ‘p’.
What is the remainder when x2018 + 2018 is divided by x – 1
Check whether p(x) is a multiple of g(x) or not:
p(x) = 2x3 – 11x2 – 4x + 5, g(x) = 2x + 1
What must be subtracted from the polynomial x3 + x2 – 2x + 1, so that the result is exactly divisible by (x – 3)?
