#### Question

Find the value of x in the following :

`2sin 3x = sqrt3`

#### Solution

We have

`2 sin 3x = sqrt3`

`=> sin 3x = sqrt3/2`

since `sin 60^@ = sqrt3/2`

Therefore

`sin 3x = sqrt3/2`

sin 3x = sin 60°

3x = 60°

`x = 60^@/3`

x = 20°

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#### APPEARS IN

Solution Find the Value of X in the Following : 2sin 3x = Square Root 3 Concept: Trigonometric Ratios.