Question
Find the value of x in the following :
`2sin 3x = sqrt3`
Solution
We have
`2 sin 3x = sqrt3`
`=> sin 3x = sqrt3/2`
since `sin 60^@ = sqrt3/2`
Therefore
`sin 3x = sqrt3/2`
sin 3x = sin 60°
3x = 60°
`x = 60^@/3`
x = 20°
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APPEARS IN
Solution Find the Value of X in the Following : 2sin 3x = Square Root 3 Concept: Trigonometric Ratios.
