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Find the Value of X in the Following : 2sin 3x = Square Root 3 - Mathematics

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प्रश्न

Find the value of x in the following :

`2sin 3x = sqrt3`

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उत्तर

We have

`2 sin 3x = sqrt3`

`=> sin 3x = sqrt3/2`

since `sin 60^@ = sqrt3/2`

Therefore

`sin 3x = sqrt3/2`

sin 3x = sin 60°

3x = 60°

`x = 60^@/3`

x = 20°

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पाठ 10: Trigonometric Ratios - Exercise 10.2 [पृष्ठ ४२]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 10 Trigonometric Ratios
Exercise 10.2 | Q 20 | पृष्ठ ४२

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