Question

Find the value of a if `[[a-b,2a+c],[2a-b,3c+d]]=[[-1,5],[0,13]]`

Answer 1

`[[a-b,2a+c],[2a-b,3c+d]]=[[-1,5],[0,13]]`

a-b=-1,2a+c=5,2a-b=0,3c+d=13

using a-b=-1 and 2a-b=0 we get a=1