English

Find the value of x, if |(2,3),(4,5)|=|(x,3),(2x,5)|. - Mathematics

Advertisements
Advertisements

Question

Find the value of x, if `|(2,3),(4,5)|=|(x,3),(2x,5)|`.

Sum
Advertisements

Solution

`|(2,3),(4,5)|=|(x,3),(2x,5)|`

⇒ 2 × 5 − 3 × 4 = x × 5 − 3 × 2x

⇒ 10 − 12 = 5x − 6x

⇒ −2 = −x

⇒ x = 2

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Determinants - Exercise 4.1 [Page 109]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 4 Determinants
Exercise 4.1 | Q 7.2 | Page 109

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the value of x, if `|(2,4),(5,1)|=|(2x, 4), (6,x)|`.


Without expanding at any stage, find the value of:

`|(a,b,c),(a+2x,b+2y,c+2z),(x,y,z)|`


Use properties of determinants to solve for x:

`|(x+a, b, c),(c, x+b, a),(a,b,x+c)| = 0` and `x != 0` 


A matrix A of order 3 × 3 has determinant 5. What is the value of |3A|?

 

A matrix of order 3 × 3 has determinant 2. What is the value of |A (3I)|, where I is the identity matrix of order 3 × 3.


A matrix A of order 3 × 3 is such that |A| = 4. Find the value of |2 A|.


If A is a 3 × 3 matrix, \[\left| A \right| \neq 0\text{ and }\left| 3A \right| = k\left| A \right|\]  then write the value of k.


Which of the following is not correct?


Show that Δ = `|(x, "p", "q"),("p", x, "q"),("q", "q", x)| = (x - "p")(x^2 + "p"x - 2"q"^2)` 


If Δ = `|(0, "b" - "a", "c" - "a"),("a" - "b", 0, "c" - "b"),("a" - "c", "b" - "c", 0)|`, then show that ∆ is equal to zero.


Let f(t) = `|(cos"t","t", 1),(2sin"t", "t", 2"t"),(sin"t", "t", "t")|`, then `lim_("t" - 0) ("f"("t"))/"t"^2` is equal to ______.


If f(x) = `|(0, x - "a", x - "b"),(x + "b", 0, x - "c"),(x + "b", x + "c", 0)|`, then ______.


If A = `[(2, lambda, -3),(0, 2, 5),(1, 1, 3)]`, then A–1 exists if ______.


There are two values of a which makes determinant, ∆ = `|(1, -2, 5),(2, "a", -1),(0, 4, 2"a")|` = 86, then sum of these number is ______.


If A is a matrix of order 3 × 3, then (A2)–1 = ______.


`|(0, xyz, x - z),(y - x, 0, y  z),(z - x, z - y, 0)|` = ______.


If A and B are matrices of order 3 and |A| = 5, |B| = 3, then |3AB| = 27 × 5 × 3 = 405.


The maximum value of `|(1, 1, 1),(1, (1 + sintheta), 1),(1, 1, 1 + costheta)|` is `1/2`


`"A" = abs ((1/"a", "a"^2, "bc"),(1/"b", "b"^2, "ac"),(1/"c", "c"^2, "ab"))` is equal to ____________.


`abs ((1 + "a", "b", "c"),("a", 1 + "b", "c"),("a", "b", 1 + "c")) =` ____________


The value of the determinant `abs ((1,0,0),(2, "cos x", "sin x"),(3, "sin x", "cos x"))` is ____________.


Find the minor of the element of the second row and third column in the following determinant `[(2,-3,5),(6,0,4),(1,5,-7)]`


Let A be a square matrix of order 2 x 2, then `abs("KA")` is equal to ____________.


Find the 5th term of expansion of `(x^2 + 1/x)^10`?


For positive numbers x, y, z, the numerical value of the determinant `|(1, log_x y, log_x z),(log_y x, 1, log_y z),(log_z x, log_z y, 1)|` is


The value of determinant `|(sin^2 13°, sin^2 77°, tan135°),(sin^2 77°, tan135°, sin^2 13°),(tan135°, sin^2 13°, sin^2 77°)|` is


In a third order matrix aij denotes the element of the ith row and the jth column.

A = `a_(ij) = {(0",", for, i = j),(1",", f or, i > j),(-1",", f or, i < j):}`

Assertion: Matrix ‘A’ is not invertible.

Reason: Determinant A = 0

Which of the following is correct?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×