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Question
Find the value of the polynomial f(y) = 6y – 3y2 + 3 at y = –1
Sum
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Solution
When y = –1
f(y) = 6y – 3y2 + 3
f(–1) = 6(–1) – 3(–1)2 + 3
= – 6 – 3 + 3
= – 6
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Chapter 3: Algebra - Exercise 3.2 [Page 91]
