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Question
Find the value of the polynomial f(y) = 6y – 3y2 + 3 at y = 0
Sum
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Solution
When y = 0
f(y) = 6y – 3y2 + 3
f(0) = 6(0) – 3(0)2 + 3
= 0 – 0 + 3
= 3
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Chapter 3: Algebra - Exercise 3.2 [Page 91]
