Advertisements
Advertisements
Question
Find the value of the letters in the following question.
8 A B C
– A B C 5
D 4 8 8
Advertisements
Solution
8 A B C
Given, – A B C 5
D 4 8 8
In the ones column, C – 5 = 8
Obviously, 13 – 5 = 8, so C = 3
In the ten’s column, B – (C + 1) = 8
⇒ B = 8 + C + 1
⇒ B = 8 + 3 + 1
⇒ B = 12 i.e. B = 2
In the hundred’s column, A – (B + 1) = 4
⇒ A = 4 + B + 1
⇒ A = 4 + 2 + 1 = 7
In the thousand’s column, 8 – A = D
⇒ 8 – 7 = D
⇒ D = 1
Hence, A = 7, B = 2, C = 3 and D = 1
APPEARS IN
RELATED QUESTIONS
| A | |
| + | A |
| + | A |
| B | A |
If 
then A = ______ and B = ______.
If 
where Q – P = 3, then find the values of P and Q.
If 1AB + CCA = 697 and there is no carry-over in addition, find the value of A + B + C.
Find the value of the letters in the following question.
B A A
+ B A A
3 A 8
Find the value of the letters in the following question.
A 0 1 B
+ 1 0 A B
B 1 0 8
If 2A7 ÷ A = 33, then find the value of A.
212 × 5 is a multiple of 3 and 11. Find the value of x.
Let E = 3, B = 7 and A = 4. Find the other digits in the sum
B A S E
+ B A L L
G A M E S
Work out the following multiplication.
12345679
× 9
Use the result to answer the following question.
What will be 12345679 × 45?
