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Question
Find the value of `sin^-1 [sin (- (17π)/8)]`.
Sum
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Solution
`sin^-1 [sin ((-17π)/8)]`
= `- sin^-1 [sin((17π)/8)]`
= `- sin^-1 [sin(2π + π/8)]`
= `- sin^-1 sin π/8`
= `- π/8`
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