Question

Find the value of `sin^-1 [sin (- (17π)/8)]`.

Answer 1

`sin^-1 [sin ((-17π)/8)]`

= `- sin^-1 [sin((17π)/8)]`

= `- sin^-1 [sin(2π + π/8)]`

= `- sin^-1 sin  π/8` 

= `- π/8`