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Question
Find the value of `cos^-1(cos (13pi)/6)`.
Sum
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Solution
`cos^-1(cos (13pi)/6) = cos^1(cos(2pi + pi/6))`
= `cos^-1(cos pi/6)`
= `pi/6`.
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Is there an error in this question or solution?
Find the value of `cos^-1(cos (13pi)/6)`.
`cos^-1(cos (13pi)/6) = cos^1(cos(2pi + pi/6))`
= `cos^-1(cos pi/6)`
= `pi/6`.