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Question
Find the value of `tan^-1 (tan (9pi)/8)`.
Sum
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Solution
`tan^-1 (tan (9pi)/8) = tan^-1 tan(pi + pi/8)`
= `tan^-1(tan (pi/8))`
= `pi/8`
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Is there an error in this question or solution?
Find the value of `tan^-1 (tan (9pi)/8)`.
`tan^-1 (tan (9pi)/8) = tan^-1 tan(pi + pi/8)`
= `tan^-1(tan (pi/8))`
= `pi/8`