Find the value of 'A', if cosec 3A = 2 √ 3

Find the value of 'A', if cosec 3A = `(2)/sqrt(3)`

Sum

cosec 3A = `(2)/sqrt(3)`

⇒ cosec 3A = cosec60°
⇒ 3A = 60°
⇒ A = 20°.

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Trigonometric Equation Problem and Solution

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Chapter 22: Trigonometrical Ratios of Standard Angles - Exercise 27.1

Chapter 22 Trigonometrical Ratios of Standard Angles
Exercise 27.1 | Q 4.3

If 2 cos 2A = `sqrt3` and A is acute,
find:
(i) A
(ii) sin 3A
(iii) sin² (75° - A) + cos² (45° +A)

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Find:
a. BC
b. AD
c. AC

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If A + B = 90°, prove that `(tan"A" tan"B" + tan"A" cot"B")/(sin"A" sec"B") - (sin^2"B")/(cos^2"A")` = tan²A