Advertisements
Advertisements
प्रश्न
Find the value of 'A', if cosec 3A = `(2)/sqrt(3)`
Advertisements
उत्तर
cosec 3A = `(2)/sqrt(3)`
⇒ cosec 3A = cosec60°
⇒ 3A = 60°
⇒ A = 20°.
APPEARS IN
संबंधित प्रश्न
If 4 cos2 x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos2 x + cot2 x
(iii) cos 3x (iv) sin 2x
Solve the following equation for A, if `sqrt3` cot 2 A = 1
Solve for x : 3 tan2 (2x - 20°) = 1
Solve for x : sin2 x + sin2 30° = 1
Find the value of 'A', if cot 3A = 1
If `sqrt(2) = 1.414 and sqrt(3) = 1.732`, find the value of the following correct to two decimal places tan60°
Find the length of AD. Given: ∠ABC = 60°, ∠DBC = 45° and BC = 24 cm.
The perimeter of a rhombus is 100 cm and obtuse angle of it is 120°. Find the lengths of its diagonals.
In the given figure; ∠B = 90°, ∠ADB = 30°, ∠ACB = 45° and AB = 24 m. Find the length of CD.
If A, B and C are interior angles of ΔABC, prove that sin`(("A" + "B")/2) = cos "C"/(2)`
