Advertisements
Advertisements
Question
Find the value of (2−1 × 4−1) ÷2−2.
Advertisements
Solution
`(2^(−1) × 4^(−1)) ÷ 2^(−2)`
= `[2^-1 xx (2^-2)^-1] ÷ 2^-2`
= `[2^-1 xx 2^-2]÷ 2^-2` ...[∵ (am)n = amn]
= `[2^(-1 + (-2))]÷2^-2` ...[∵ am × an = am+n]1
= `[2^(-1-2) ÷ 2^-2]`
= `2^-3 ÷ 2^-2`
= `2^(-3 - (-2))` .....[∵ am ÷ an = am−n]
= 2−3+2 = 2−1
= `1/2`
APPEARS IN
RELATED QUESTIONS
Simplify.
`(3^(-5) xx 10^(-5) xx 125)/(5^(-7) xx 6^(-5))`
Express the following as a rational number of the form \[\frac{p}{q},\] where p and q are integers and q ≠ 0.
Find the value of the following:
3−1 + 4−1
Evaluate:
\[\left( \frac{- 1}{2} \right)^{- 1}\]
Cube of \[\frac{- 1}{2}\] is
Which of the following is not reciprocal of \[\left( \frac{2}{3} \right)^4 ?\]
For any two non-zero rational numbers a and b, a4 ÷ b4 is equal to
For a fixed base, if the exponent decreases by 1, the number becomes ______.
The multiplicative inverse of 10–100 is ______.
The multiplicative inverse of `(3/2)^2` is not equal to `(2/3)^-2`.
