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Question
Find the third proportional to $$\left(\frac{a}{b} +\frac{b}{a}\right)$$ and $$\sqrt{a^2 + b^2}$$.
Sum
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Solution
If $$x$$ is the third proportional to $$a$$ and $$b$$, then $$a : b :: b : x \Rightarrow x = \frac{b^2}{a}$$.
$$a = \frac{a}{b} + \frac{b}{a} = \frac{a^2 + b^2}{ab}$$ and $$b = \sqrt{a^2 + b^2}$$
$$x = \frac{(\sqrt{a^2 + b^2})^2}{\frac{a^2 + b^2}{ab}}$$
$$= \frac{(a^2 + b^2) \times ab}{a^2 + b^2}$$
$$= ab$$
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