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Question
Find the sum of the following series
51 + 52 + 53 + ... + 92
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Solution
51 + 52 + 53 + ... + 92
= (1 + 2 + 3 + ... + 92) – (1 + 2 + 3 + ... + 50)
= `sum_1^92 "n" - sum_1^50 "n"`
= `(("n"("n" + 1))/2)_("n" = 92) - (("n"("n" + 1))/2)_("n" = 50)`
= `(92 xx 93)/2 - (50 xx 51)/2`
= 4278 – 1275
= 3003
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