Advertisements
Advertisements
Question
If 1 + 2 + 3 + ... + k = 325, then find 13 + 23 + 33 + ... + k3
Advertisements
Solution
1 + 2 + 3 + … + k = 325
13 + 23 + 33 + ... + k3 = `sum_1^"n" "n"^3`
= `(("n"("n" + 1))/2)^2`
= `(sum_1^"n" "n")^2`
If 1 + 2 + 3 + … + k = 325
13 + 23 + 33 + … + k3 = (325)2
= 105625
APPEARS IN
RELATED QUESTIONS
Find the sum of the following series
1 + 2 + 3 + ... + 60
Find the sum of the following series
3 + 6 + 9 + ... + 96
Find the sum of the following series
62 + 72 + 82 + ... + 212
Find the sum of the following series
103 + 113 + 123 + ... + 203
How many terms of the series 13 + 23 + 33 + … should be taken to get the sum 14400?
The sum of the cubes of the first n natural numbers is 2025, then find the value of n
Find the sum of the series (23 – 13) + (43 – 33) + (63 – 153) + ... to n terms
Find the sum of the series (23 – 13) + (43 – 33) + (63 – 153) + ... to 8 terms
The value of (13 + 23 + 33 + ... + 153) – (1 + 2 + 3 + ... + 15) is
The value of a motorcycle depreciates at a rate of 15% per year. What will be the value of the motorcycle for 3 year hence, which is now purchased for ₹ 45,000?
