Advertisements
Advertisements
Question
If 1 + 2 + 3 + ... + k = 325, then find 13 + 23 + 33 + ... + k3
Advertisements
Solution
1 + 2 + 3 + … + k = 325
13 + 23 + 33 + ... + k3 = `sum_1^"n" "n"^3`
= `(("n"("n" + 1))/2)^2`
= `(sum_1^"n" "n")^2`
If 1 + 2 + 3 + … + k = 325
13 + 23 + 33 + … + k3 = (325)2
= 105625
APPEARS IN
RELATED QUESTIONS
Find the sum of the following series
1 + 2 + 3 + ... + 60
Find the sum of the following series
51 + 52 + 53 + ... + 92
Find the sum of the following series
62 + 72 + 82 + ... + 212
Find the sum of the following series
1 + 3 + 5 + ... + 71
If 13 + 23 + 33 + ... + k3 = 44100 then find 1 + 2 + 3 + ... + k
How many terms of the series 13 + 23 + 33 + … should be taken to get the sum 14400?
Rekha has 15 square colour papers of sizes 10 cm,11 cm,12 cm, …, 24 cm. How much area can be decorated with these colour papers?
Find the sum of the series (23 – 13) + (43 – 33) + (63 – 153) + ... to n terms
Find the sum of the series (23 – 13) + (43 – 33) + (63 – 153) + ... to 8 terms
The value of a motorcycle depreciates at a rate of 15% per year. What will be the value of the motorcycle for 3 year hence, which is now purchased for ₹ 45,000?
