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Find the sum of the first 22 terms of the A.P. : 8, 3, –2, ………

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Question

Find the sum of the first 22 terms of the A.P. : 8, 3, –2, ………

Sum
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Solution

The given A.P. is 8, 3, –2, ………

Here, a = 8, d = 3 – 8 = –5 and n = 22

∴ `S = n/2[2a + (n - 1)d]`

= `22/2 [2 xx 8 + (22 - 1) xx (-5)]`

= 11[16 + 21 × (–5)]

= 11[16 – 105]

= 11 × (–89)

= –979

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