Advertisements
Advertisements
प्रश्न
Find the sum of the first 22 terms of the A.P. : 8, 3, –2, ………
Advertisements
उत्तर
The given A.P. is 8, 3, –2, ………
Here, a = 8, d = 3 – 8 = –5 and n = 22
∴ `S = n/2[2a + (n - 1)d]`
= `22/2 [2 xx 8 + (22 - 1) xx (-5)]`
= 11[16 + 21 × (–5)]
= 11[16 – 105]
= 11 × (–89)
= –979
APPEARS IN
संबंधित प्रश्न
Find the sum given below:
–5 + (–8) + (–11) + ... + (–230)
The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceeds the second term by 6, find three terms.
Find the sum of all odd numbers between 100 and 200.
Find the sum of all multiples of 9 lying between 300 and 700.
Find the first term and common difference for the A.P.
0.6, 0.9, 1.2,1.5,...
Find whether 0 (zero) is a term of the A.P. 40, 37, 34, 31,... .
The common difference of an A.P., the sum of whose n terms is Sn, is
Find the value of x, when in the A.P. given below 2 + 6 + 10 + ... + x = 1800.
If a = 6 and d = 10, then find S10.
In an A.P., if Sn = n(4n + 1), find the A.P.
