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Question
Find the sum of first fifteen multiples of 8.
Sum
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Solution
First fifteen multiples of 8 are 8, 16, 24, ..., 120.
Here $$a = 8, \ d = 8, \ n = 15$$.
$$S_{15} = \frac{15}{2}[2(8) + 14(8)]$$
$$= \frac{15}{2}(16 + 112)$$
$$= 15(64)$$
$$= 960$$
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Chapter 10: Arithmetic Progression - EXERCISE 10B [Page 167]
