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Find the Sum, Invested at 10% Compounded Annually, on Which the Interest for the Third Year Exceeds the Interest of the First Year by Rs 252.

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Question

Find the sum, invested at 10% compounded annually, on which the interest for the third year exceeds the interest of the first year by Rs. 252.

Sum
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Solution

Let the sum of money be Rs.100.
Rate of interest = 10% p.a.
Interest at the end of 1st year = 10% of Rs. 100 = Rs. 10
Amount at the end of 1st year = Rs. 100 + Rs. 10 = Rs. 110
Interest at the end of 2nd year = 10% of Rs. 110 = Rs. 11
Amount at the end of 2nd year = Rs. 110 + Rs. 11 = Rs.121
Interest at the end of 3rd year =10% of Rs. 121= Rs. 12.10
Difference between interest of 3rd year and 1st year
= Rs. 12.10 - Rs. 10 = Rs. 2.10
When difference is Rs. 2.10, principal is Rs. 100
When difference is Rs. 252, principal = `[100 xx 252]/2.10` = Rs.12,000.

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Chapter 2: Compound Interest (Without using formula) - Exercise 2 (C) [Page 38]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 2 Compound Interest (Without using formula)
Exercise 2 (C) | Q 10 | Page 38

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