Advertisements
Advertisements
Question
Find the difference between the compound interest and simple interest. On a sum of Rs 50,000 at 10% per annum for 2 years.
Advertisements
Solution
Given:
P = Rs 50, 000
R = 10 % p. a.
n = 2 years
We know that amount A at the end of n years at the rate R % per annum when the interest is
compounded annually is given by A = P\[\left( 1 + \frac{R}{100} \right) . \]
\[ \therefore\text{ A = Rs }50, 000 \left( 1 + \frac{10}{100} \right)^2 \]
\[ =\text{ Rs }50, 000 \left( 1 . 1 \right)^2 \]
= Rs 60, 500
Also,
CI = A - P
= Rs 60, 500 - Rs 50, 000
= Rs 10, 500
We know that:
\[SI = \frac{PRT}{100}\]
\[ = \frac{50, 000 \times 10 \times 2}{100}\]
= Rs 10, 000
∴ Difference between CI and SI = Rs 10, 500 - Rs 10, 000
= Rs 500
RELATED QUESTIONS
Calculate the amount and compound interest on Rs 10000 for 1 year at 8% per annum compounded half yearly.
What sum will amount of Rs. 6,593.40 in 2 years at C.I. , if the rates are 10 per cent and 11 per cent for the two successive years ?
The simple interest on a certain sum of money at 4% p.a. for 2 years is Rs1500. What will be the compound interest on the same sum for the same time?
Find the difference between simple and compound interest on Rs 5000 invested for 3 years at 6% p.a., interest payable yearly.
The simple interest on a certain sum for 3 years at 4% is Rs 600. Find the compound interest for the same sum at the same percent and in the same time.
The compound interest on ₹ 8000 at 10% p.a for 1 year, compounded half yearly is ____________
Find the compound interest on ₹ 3200 at 2.5% p.a for 2 years, compounded annually
Find the C.I. on ₹ 15000 for 3 years if the rates of interest are 15%, 20% and 25% for the I, II and III years respectively
The cost of a machine is ₹ 18000 and it depreciates at `16 2/3 %` annually. Its value after 2 years will be ___________
