Advertisements
Advertisements
Question
The present population of a town is 28000. If it increases at the rate of 5% per annum, what will be its population after 2 years?
Advertisements
Solution
Here,
P = Initial population = 28, 000
R = Rate of growth of population = 5 % per annum
n = Number of years = 2
∴ Population after two years = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[ = 28, 000 \left( 1 + \frac{5}{100} \right)^2 \]
\[ = 28, 000 \left( 1 . 05 \right)^2 \]
= 30, 870
Hence, the population after two years will be 30, 870.
RELATED QUESTIONS
Calculate the amount and compound interest on Rs 10800 for 3 years at `12 1/2` % per annum compounded annually.
Ramesh invests Rs. 12,800 for three years at the rate of 10% per annum compound interest. Find:
- the sum due to Ramesh at the end of the first year.
- the interest he earns for the second year.
- the total amount due to him at the end of the third year.
A man borrows Rs.10,000 at 10% compound interest compounded yearly. At the end of each year, he pays back 30% of the sum borrowed. How much money is left unpaid just after the second year ?
Saurabh invests Rs. 48,000 for 7 years at 10% per annum compound interest. Calculate:
(i) the interest for the first year.
(ii) the amount at the end of second year.
(iii) the interest for the third year.
Calculate the amount and the compound interest on Rs. 10,000 in 3 years at 8% per annum.
Calculate the compound interest for the second year on Rs. 15000 invested for 5 years at 6% per annum.
The simple interest on a certain sum of money at 4% p.a. for 2 years is Rs1500. What will be the compound interest on the same sum for the same time?
The simple interest on a certain sum for 3 years at 4% is Rs 600. Find the compound interest for the same sum at the same percent and in the same time.
Find the C.I. on ₹ 15000 for 3 years if the rates of interest are 15%, 20% and 25% for the I, II and III years respectively
The time taken for ₹ 4400 to become ₹ 4851 at 10%, compounded half yearly is _______
