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The Present Population of a Town is 28000. If It Increases at the Rate of 5% per Annum, What Will Be Its Population After 2 Years?

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Question

The present population of a town is 28000. If it increases at the rate of 5% per annum, what will be its population after 2 years?

Sum
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Solution

Here,
P = Initial population = 28, 000
R = Rate of growth of population = 5 % per annum
n = Number of years = 2
∴ Population after two years = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[ = 28, 000 \left( 1 + \frac{5}{100} \right)^2 \]
\[ = 28, 000 \left( 1 . 05 \right)^2 \]
= 30, 870
Hence, the population after two years will be 30, 870.

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Chapter 14: Compound Interest - Exercise 14.4 [Page 27]

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RD Sharma Mathematics [English] Class 8
Chapter 14 Compound Interest
Exercise 14.4 | Q 1 | Page 27

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