Advertisements
Advertisements
प्रश्न
The present population of a town is 28000. If it increases at the rate of 5% per annum, what will be its population after 2 years?
Advertisements
उत्तर
Here,
P = Initial population = 28, 000
R = Rate of growth of population = 5 % per annum
n = Number of years = 2
∴ Population after two years = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[ = 28, 000 \left( 1 + \frac{5}{100} \right)^2 \]
\[ = 28, 000 \left( 1 . 05 \right)^2 \]
= 30, 870
Hence, the population after two years will be 30, 870.
संबंधित प्रश्न
Calculate the amount and compound interest on Rs 10800 for 3 years at `12 1/2` % per annum compounded annually.
Find the difference between the compound interest and simple interest. On a sum of Rs 50,000 at 10% per annum for 2 years.
Simple interest on a sum of money for 2 years at \[6\frac{1}{2} %\] per annum is Rs 5200. What will be the compound interest on the sum at the same rate for the same period?
At what rate percent per annum will a sum of Rs 4000 yield compound interest of Rs 410 in 2 years?
In how many years ₹ 700 will amount to ₹ 847 at a compound interest rate of 10 p.c.p.a.
A sum is invested at compound interest, compounded yearly. If the interest for two successive years is Rs. 5,700 and Rs. 7,410. calculate the rate of interest.
A man borrows Rs.10,000 at 10% compound interest compounded yearly. At the end of each year, he pays back 20% of the amount for that year. How much money is left unpaid just after the second year ?
Calculate the difference between the compound interest and the simple interest on ₹ 8,000 in three years and at 10% per annum.
Find the C.I. on ₹ 15000 for 3 years if the rates of interest are 15%, 20% and 25% for the I, II and III years respectively
The compound interest on Rs 50,000 at 4% per annum for 2 years compounded annually is ______.
