Advertisements
Advertisements
प्रश्न
Rachana borrowed a certain sum at the rate of 15% per annum. If she paid at the end of two years Rs 1290 as interest compounded annually, find the sum she borrowed.
Advertisements
उत्तर
Let the money borrowed by Rachana be Rs x.
Then, we have:
\[CI = P \left( 1 + \frac{R}{100} \right)^n - P\]
\[1, 290 = x\left[ \left( 1 + \frac{15}{100} \right)^2 - 1 \right]\]
\[1, 290 = x\left[ 0 . 3225 \right]\]
\[x = \frac{1, 290}{0 . 3225}\]
\[ = 4, 000\]
Thus, Rachana borrowed Rs 4, 000.
APPEARS IN
संबंधित प्रश्न
A certain sum amounts to Rs. 5,292 in two years and Rs. 5,556.60 in three years, interest being compounded annually. Find : the rate of interest.
What sum will amount of Rs. 6,593.40 in 2 years at C.I. , if the rates are 10 per cent and 11 per cent for the two successive years ?
Calculate the amount and the compound interest on Rs. 12,000 in 2 years and at 10% per year.
Calculate the compound interest on Rs. 5,000 in 2 years; if the rates of interest for successive years be 10% and 12% respectively.
Calculate the difference between the compound interest and the simple interest on ₹ 8,000 in three years and at 10% per annum.
Rohit borrowed ₹ 40,000 for 2 years at 10% per annum C.I. and Manish borrowed the same sum for the same time at 10.5% per annum simple interest. Which of these two gets less interest and by how much?
A certain sum of money invested for 5 years at 8% p.a. simple interest earns an interest of ₹ 12,000. Find:
(i) the sum of money.
(ii) the compound interest earned by this money in two years and at 10% p.a. compound interest.
A principal becomes ₹ 2028 in 2 years at 4% p.a compound interest. Find the principal
Find the difference between Compound Interest and Simple Interest on Rs 45,000 at 12% per annum for 5 years.
