Advertisements
Advertisements
प्रश्न
Find the difference between Compound Interest and Simple Interest on Rs 45,000 at 12% per annum for 5 years.
Advertisements
उत्तर
Principal (P) = ₹ 45000
Rate of interest (R) = 12% per annum
Time period (T) = 5 year
Simple interest, `SI = (P xx R xx T)/100`
= `(45000 xx 12 xx 5)/100`
= 450 × 60
= ₹ 27000
∵ Compound interest, CI = A – P
Where, `A = P(1 + R/100)^T`
`A = 45000(1 + 12/100)^5`
= `45000(28/25)^5`
= `45000 xx 28/25 xx 28/25 xx 28/25 xx 28/25 xx 28/25`
= `(45000 xx 17210368)/9765625`
= 45000 × 1.76
= ₹ 79200
∴ Compound interest, CI = ₹ 79200 – ₹ 45000 = ₹ 34200
∴ Difference between SI and CI = ₹ 34200 – ₹ 27000 = ₹ 7200
APPEARS IN
संबंधित प्रश्न
The difference between the compound interest and simple interest on a certain sum for 2 years at 7.5% per annum is Rs 360. Find the sum.
The present population of a town is 28000. If it increases at the rate of 5% per annum, what will be its population after 2 years?
The cost of a machine depreciated by Rs. 4,000 during the first year and by Rs. 3,600 during the second year. Calculate :
- The rate of depreciation.
- The original cost of the machine.
- Its cost at the end of the third year.
What sum will amount of Rs. 6,593.40 in 2 years at C.I. , if the rates are 10 per cent and 11 per cent for the two successive years ?
A sum of Rs. 13,500 is invested at 16% per annum compound interest for 5years. Calculate :
(i) the interest for the first year.
(ii) the amount at the end of first year.
(iii) the interest for the second year, correct to the nearest rupee.
Calculate the difference between the compound interest and the simple interest on ₹ 7,500 in two years and at 8% per annum.
Peter borrows ₹ 12,000 for 2 years at 10% p.a. compound interest. He repays ₹ 8,000 at the end of the first year. Find:
- the amount at the end of the first year, before making the repayment.
- the amount at the end of the first year, after making the repayment.
- the principal for the second year.
- the amount to be paid at the end of the second year, to clear the account.
The annual rate of growth in population of a town is 10%. If its present population is 26620, then the population 3 years ago was _________
Find the rate of compound interest at which a principal becomes 1.69 times itself in 2 years
To calculate the growth of a bacteria if the rate of growth is known, the formula for calculation of amount in compound interest can be used.
