Advertisements
Advertisements
प्रश्न
Find the compound interest for `2 1/2` years on ₹ 4000 at 10% p.a, if the interest is compounded yearly
Advertisements
उत्तर
Principal (P) = ₹ 4000
r = 10% p.a
Compounded yearly
n = `2 1/2` years.
Since it is of the form `"a" "b"/"c"` years
Amount (A) = `(1 + "r"/100)^"n" (1 + ("b"/"c" xx "r")/100)`
= `4000(1 + 10/100)^2 (1 + (1/2 xx 10)/100)^1`
= `4000 xx (110/100)^2 xx (105/100)^1`
= 4000 × 1.1 × 1.1 × 1.05
= 5082
∴ C.I. = Amount – Principal
= 5082 – 4000
= 1082
APPEARS IN
संबंधित प्रश्न
Calculate the amount and compound interest on Rs 8000 for 1 year at 9% per annum compound half yearly. (You could use the year by year calculation using SI formula to verify)
Find the difference between the compound interest and simple interest. On a sum of Rs 50,000 at 10% per annum for 2 years.
The interest on a sum of Rs 2000 is being compounded annually at the rate of 4% per annum. Find the period for which the compound interest is Rs 163.20.
The difference in simple interest and compound interest on a certain sum of money at \[6\frac{2}{3} %\] per annum for 3 years is Rs 46. Determine the sum.
Ramesh invests Rs. 12,800 for three years at the rate of 10% per annum compound interest. Find:
- the sum due to Ramesh at the end of the first year.
- the interest he earns for the second year.
- the total amount due to him at the end of the third year.
During every financial year, the value of a machine depreciates by 12%. Find the original cost of a machine which depreciates by Rs. 2,640 during the second financial year of its purchase.
Rekha borrowed Rs. 40,000 for 3 years at 10% per annum compound interest. Calculate the interest paid by her for the second year.
Calculate the compound interest for the second year on Rs. 15000 invested for 5 years at 6% per annum.
Find the amount and the compound interest payable annually on the following :
Rs.25000 for 1`(1)/(2)` years at 10% per annum.
Suppose for the principal P, rate R% and time T, the simple interest is S and compound interest is C. Consider the possibilities.
- C > S
- C = S
- C < S
Then
