मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ८

Find the compound interest for 212 years on ₹ 4000 at 10% p.a, if the interest is compounded yearly

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प्रश्न

Find the compound interest for `2 1/2` years on ₹ 4000 at 10% p.a, if the interest is compounded yearly

बेरीज
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उत्तर

Principal (P) = ₹ 4000

r = 10% p.a

Compounded yearly

n = `2 1/2` years.

Since it is of the form `"a" "b"/"c"` years

Amount (A) = `(1 + "r"/100)^"n" (1 + ("b"/"c" xx "r")/100)`

= `4000(1 + 10/100)^2 (1 + (1/2 xx 10)/100)^1`

= `4000 xx (110/100)^2 xx (105/100)^1`

= 4000 × 1.1 × 1.1 × 1.05

= 5082

∴ C.I. = Amount – Principal

= 5082 – 4000

= 1082

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पाठ 4: Life Mathematics - Exercise 4.3 [पृष्ठ १३९]

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सामाचीर कलवी Mathematics [English] Class 8 TN Board
पाठ 4 Life Mathematics
Exercise 4.3 | Q 4 | पृष्ठ १३९

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