Advertisements
Advertisements
प्रश्न
The difference between the compound interest and simple interest on a certain sum for 2 years at 7.5% per annum is Rs 360. Find the sum.
Advertisements
उत्तर
Let the sum be P .
Thus, we have:
CI - SI = 360
\[\left[ P \left( 1 + \frac{R}{100} \right)^n - P \right] - \frac{P \times 7 . 5 \times 2}{100} = 360\]
\[P\left[ \left( 1 + \frac{7 . 5}{100} \right)^2 - 1 \right] - \frac{P \times 7 . 5 \times 2}{100} = 360\]
\[P\left[ 1 . 155625 - 1 \right] - \] 0.15P= 3600.155625P - 0.15P=3600.005625P= 360p=`360/0.005625P` = 64000
Thus, the required sum is Rs. 64.
APPEARS IN
संबंधित प्रश्न
The interest on a sum of Rs 2000 is being compounded annually at the rate of 4% per annum. Find the period for which the compound interest is Rs 163.20.
At what rate percent per annum will a sum of Rs 4000 yield compound interest of Rs 410 in 2 years?
A sum is invested at compound interest, compounded yearly. If the interest for two successive years is Rs. 5,700 and Rs. 7,410. calculate the rate of interest.
Rs. 8,000 is lent out at 7% compound interest for 2 years. At the end of the first year Rs. 3,560 are returned. Calculate :
(i) the interest paid for the second year.
(ii) the total interest paid in two years.
(iii) the total amount of money paid in two years to clear the debt.
The value of a machine depreciated by 10% per year during the first two years and 15% per year during the third year. Express the total depreciation of the machine, as percent, during the three years.
A man invests Rs. 9600 at 10% per annum compound interest for 3 years. Calculate :
(i) the interest for the first year.
(ii) the amount at the end of the first year.
(iii) the interest for the second year.
(iv) the interest for the third year. the interest for the first year.
Find the amount and the compound interest payable annually on the following :
Rs.25000 for 1`(1)/(2)` years at 10% per annum.
The difference between C.I. payable annually and S.I. on Rs.50,000 for two years is Rs.125 at the same rate of interest per annum. Find the rate of interest.
The present value of a machine is ₹ 16800. It depreciates at 25% p.a. Its worth after 2 years is ₹ 9450
Find the compound interest for `2 1/2` years on ₹ 4000 at 10% p.a, if the interest is compounded yearly
