Advertisements
Advertisements
प्रश्न
In how much time would Rs 5000 amount to Rs 6655 at 10% per annum compound interest?
Advertisements
उत्तर
Let the time period be n years.
Thus, we have:
\[\text{ CI = P }\left( 1 + \frac{R}{100} \right)^n - P\]
\[6, 655 = 5, 000 \left( 1 + \frac{10}{100} \right)^n - 5, 000\]
\[11, 655 = 5, 000 \left( 1 . 10 \right)^n \]
\[ \left( 1 . 1 \right)^n = \frac{11, 655}{5, 000}\]
\[ \left( 1 . 1 \right)^n = 2 . 331\]
\[ \left( 1 . 1 \right)^n = \left( 1 . 1 \right)^3 \]
On comparing both the sides, we get:
n = 3
Thus, the required time is three years.
संबंधित प्रश्न
Calculate the amount and compound interest on Rs 8000 for 1 year at 9% per annum compound half yearly. (You could use the year by year calculation using SI formula to verify)
In how many years ₹ 700 will amount to ₹ 847 at a compound interest rate of 10 p.c.p.a.
Mohit invests Rs. 8,000 for 3 years at a certain rate of interest, compounded annually. At the end of one year it amounts to Rs. 9,440. Calculate:
- the rate of interest per annum.
- the amount at the end of the second year.
- the interest accrued in the third year.
Rekha borrowed Rs. 40,000 for 3 years at 10% per annum compound interest. Calculate the interest paid by her for the second year.
Calculate the difference between the compound interest and the simple interest on ₹ 8,000 in three years and at 10% per annum.
Find the amount and the compound interest payable annually on the following :
Rs.25000 for 1`(1)/(2)` years at 10% per annum.
The time taken for ₹ 1000 to become ₹ 1331 at 20% p.a, compounded annually is 3 years
The cost of a machine is ₹ 18000 and it depreciates at `16 2/3 %` annually. Its value after 2 years will be ___________
Find the difference between Compound Interest and Simple Interest on Rs 45,000 at 12% per annum for 5 years.
