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Question
Find the sum 32 + 30 + 28 + .................... + 10.
Sum
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Solution
Here, $$a = 32, \ d = -2, \ l = 10$$.
$$32 + (n - 1)(-2) = 10$$
$$\Rightarrow n = 12$$
$$S_{12} = \frac{12}{2}(32 + 10)$$
$$= 6(42)$$
$$= 252$$
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