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Find the Smallest Number Which, When Divided by 12, 15, 18, 24 and 36 Leaves No Remainder - Mathematics

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Question

Find the smallest number which, when divided by 12, 15, 18, 24 and 36 leaves no remainder

Sum
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Solution

The least number which is exactly divisible by each given number is their L.C.M. Required number L.C.M. of 12, 15, 18, 24 and 36.

2 12, 15, 18, 24, 36
2 6, 15, 9, 12, 18
3 3, 15, 9, 6, 9
3 1, 5, 3, 2, 3
  1, 5, 1, 2, 1

∴ L.C.M. = Least required number
= 2 x 2 x 3 x 3 x 5 x 2 = 360

Hence, the least required number = 360

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Chapter 8: HCF and LCM - Exercise 8 (C)

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Selina Mathematics [English] Class 6
Chapter 8 HCF and LCM
Exercise 8 (C) | Q 6
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