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प्रश्न
Find the smallest number which, when divided by 12, 15, 18, 24 and 36 leaves no remainder
बेरीज
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उत्तर
The least number which is exactly divisible by each given number is their L.C.M. Required number L.C.M. of 12, 15, 18, 24 and 36.
| 2 | 12, | 15, | 18, | 24, | 36 |
| 2 | 6, | 15, | 9, | 12, | 18 |
| 3 | 3, | 15, | 9, | 6, | 9 |
| 3 | 1, | 5, | 3, | 2, | 3 |
| 1, | 5, | 1, | 2, | 1 |
∴ L.C.M. = Least required number
= 2 x 2 x 3 x 3 x 5 x 2 = 360
Hence, the least required number = 360
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